43x-18x^2=0

Solution for 43x-18x^2=0 equation:

43x-18x^2=0

a = -18; b = 43; c = 0;
Δ = b2-4ac
Δ = 432-4·(-18)·0
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-43}{2*-18}=\frac{-86}{-36}
=2+7/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+43}{2*-18}=\frac{0}{-36}
=0
$